출처 :<a href="https://stackoverflow.com/questions/4486787/jackson-with-json-unrecognized-field-not-marked-as-ignorable"> https://stackoverflow.com/questions/4486787/jackson-with-json-unrecognized-field-not-marked-as-ignorable</a>&nbsp;&nbsp;<h3>class annotation</h3><pre style="background-color:#2b2b2b;color:#a9b7c6;font-family:'D2Coding',monospace;font-size:11.3pt;">import com.fasterxml.jackson.annotation.JsonIgnoreProperties; @JsonIgnoreProperties(ignoreUnknown = true) public class MyClass { }</pre>&nbsp;&nbsp;<h3>in function</h3><pre style="background-color:#2b2b2b;color:#a9b7c6;font-family:'D2Coding',monospace;font-size:11.3pt;">ObjectMapper objectMapper = new ObjectMapper(); objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false); SearchObjectDto dto = objectMapper.readValue(decodedQuery, SearchObjectDto.class);</pre>&nbsp;&nbsp;<h3>application.properties</h3><pre style="background-color:#2b2b2b;color:#a9b7c6;font-family:'D2Coding',monospace;font-size:11.3pt;">spring.jackson.deserialization.fail-on-unknown-properties=false</pre>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;

Jackson json deserialize시에 포함하지 않는 properties 무시하기